(x^3+5x-18)/(x-2)

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Solution for (x^3+5x-18)/(x-2) equation: 


D( x )

x-2 = 0

x-2 = 0

x-2 = 0

x-2 = 0 // + 2

x = 2

x in (-oo:2) U (2:+oo)

(x^3+5*x-18)/(x-2) = 0

x^3+5*x-18 = 0

x^3+5*x-18 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6, 9, -9, 18, -18 }

1

x = 1

x^3+5*x-18 = -12

1

-1

x = -1

x^3+5*x-18 = -24

-1

2

x = 2

x^3+5*x-18 = 0

2

x-2

x^2+2*x+9

x^3+5*x-18

x-2

2*x^2-x^3

2*x^2+5*x-18

4*x-2*x^2

9*x-18

18-9*x

0

x^2+2*x+9 = 0

DELTA = 2^2-(1*4*9)

DELTA = -32

DELTA < 0

x in { 2} 

x-2 = 0

1 = 0

x belongs to the empty set

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